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	<title>Acceleration due to gravity - Revision history</title>
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	<updated>2026-05-04T04:31:03Z</updated>
	<subtitle>Revision history for this page on the wiki</subtitle>
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		<id>https://mech.subwiki.org/w/index.php?title=Acceleration_due_to_gravity&amp;diff=491&amp;oldid=prev</id>
		<title>Vipul: Created page with &quot;==Definition==  &#039;&#039;&#039;Acceleration due to gravity&#039;&#039;&#039; refers to the value of the acceleration on one body due to another that &#039;&#039;would&#039;&#039; arise as a result of the [[gravitational force...&quot;</title>
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		<updated>2011-08-24T15:48:06Z</updated>

		<summary type="html">&lt;p&gt;Created page with &amp;quot;==Definition==  &amp;#039;&amp;#039;&amp;#039;Acceleration due to gravity&amp;#039;&amp;#039;&amp;#039; refers to the value of the acceleration on one body due to another that &amp;#039;&amp;#039;would&amp;#039;&amp;#039; arise as a result of the [[gravitational force...&amp;quot;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;==Definition==&lt;br /&gt;
&lt;br /&gt;
&amp;#039;&amp;#039;&amp;#039;Acceleration due to gravity&amp;#039;&amp;#039;&amp;#039; refers to the value of the acceleration on one body due to another that &amp;#039;&amp;#039;would&amp;#039;&amp;#039; arise as a result of the [[gravitational force]] between the bodies, &amp;#039;&amp;#039;if&amp;#039;&amp;#039; there were no other forces on that body. In other words, that body is in [[free fall]].&lt;br /&gt;
&lt;br /&gt;
===The case of the earth or a large planet===&lt;br /&gt;
&lt;br /&gt;
Consider the [[earth]] and an object near the surface of the earth, so that, for practical purposes, the distance between their [[center of mass|centers of mass]] can be taken to be the radius of the earth. If &amp;lt;math&amp;gt;M&amp;lt;/math&amp;gt; is the [[mass]] of the earth, &amp;lt;math&amp;gt;R&amp;lt;/math&amp;gt; is the radius of the earth, and &amp;lt;math&amp;gt;m&amp;lt;/math&amp;gt; is the mass of this other object, then the magnitude of gravitational force exerted by the earth on the object is:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;F_{\operatorname{grav}} = \frac{GMm}{R^2}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
where &amp;lt;math&amp;gt;G&amp;lt;/math&amp;gt; is the [[gravitational constant]]. &amp;#039;&amp;#039;If&amp;#039;&amp;#039; the body with mass &amp;lt;math&amp;gt;m&amp;lt;/math&amp;gt; were in [[free fall]], [[Newton&amp;#039;s second law of motion]] would yield:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;ma = \frac{GMm}{R^2}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
where &amp;lt;math&amp;gt;a&amp;lt;/math&amp;gt; is the acceleration of the body in the direction of the center of the earth (i.e., downward). We thus get:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;a = \frac{GM}{R^2}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Note that the quantity on the right side is independent of &amp;lt;math&amp;gt;m&amp;lt;/math&amp;gt;, and this quantity is called the &amp;#039;&amp;#039;acceleration due to gravity&amp;#039;&amp;#039;, and is denoted by the letter &amp;lt;math&amp;gt;g&amp;lt;/math&amp;gt;. We thus get:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;g = \frac{GM}{R^2}&amp;lt;/math&amp;gt;&lt;/div&gt;</summary>
		<author><name>Vipul</name></author>
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