Traction - Revision history

Vipul: /* On an incline */

2011-08-24T13:11:24Z

On an incline

← Older revision		Revision as of 13:11, 24 August 2011
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	===On an incline===		===On an incline===

	~~We need~~ to ~~use~~ the ~~model of~~ [[~~sliding-cum-rotational motion along an inclined plane~~]]. ~~{{fillin}}~~		If <math>\alpha</math> is the angle of the incline, the ''maximum'' possible traction along the incline (whether going up or down the incline) is <math>\mu_smg\cos \alpha</math> where <math>m</math> is the mass of the vehicle. The maximum possible magnitude of acceleration is thus <math>\mu_sg\cos \alpha</math>.

			What this means is that along an incline, for the ''same'' pair of surfaces, the traction that can be achieved is less. In other words, it is harder to accelerate or decelerate a vehicle up or down an incline while making sure that the [[no slip condition]] is preserved.

Vipul at 13:05, 24 August 2011

2011-08-24T13:05:55Z

← Older revision		Revision as of 13:05, 24 August 2011
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	==Value of traction==		==Value of traction==

	===On a horizontal road===		===On a horizontal road ignoring downforce===

	If we assume the [[Coulomb model of friction]], then, on a horizontal road, we have:		If we assume the [[Coulomb model of friction]], then, on a horizontal road, we have:
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	Here <math>g</math> denotes the value of [[acceleration due to gravity]].		Here <math>g</math> denotes the value of [[acceleration due to gravity]].

			In particular, the more slippery a surface, the lower the value of <math>\mu_s</math>, and the lower the maximum value of traction that can be achieved on the surface.

	===On an incline===		===On an incline===

	We need to use the model of [[sliding-cum-rotational motion along an inclined plane]]. {{fillin}}		We need to use the model of [[sliding-cum-rotational motion along an inclined plane]]. {{fillin}}

Vipul: /* On an incline */

2011-08-24T12:32:46Z

On an incline

← Older revision		Revision as of 12:32, 24 August 2011
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	===On an incline===		===On an incline===

	We need to use the model of [[~~rolling~~ motion along an inclined plane]]. {{fillin}}		We need to use the model of [[sliding-cum-rotational motion along an inclined plane]]. {{fillin}}

Vipul: Created page with "==Definition== '''Traction''' refers to the maximum possible value of friction force between a car and the road/ground on which it is running, for which the [[no slip condit..."

2011-08-24T10:42:08Z

Created page with "==Definition== '''Traction''' refers to the maximum possible value of friction force between a car and the road/ground on which it is running, for which the [[no slip condit..."

New page

==Definition==

'''Traction''' refers to the maximum possible value of [[friction]] force between a car and the road/ground on which it is running, for which the [[no slip condition]] is maintained, i.e., the wheels (of the tires) keep [[rolling]].

It thus represents the maximum value of [[force]] that can be applied to accelerate or decelerate the car while maintaining the no slip condition.

==Value of traction==

===On a horizontal road===

If we assume the [[Coulomb model of friction]], then, on a horizontal road, we have:

Traction = [[Limiting coefficient of static friction]] (between the tires and the road) <math>\times</math> [[Weight]] of the car.

If the [[limiting coefficient of static friction]] is <math>\mu_s</math>, the maximum achievable magnitude of acceleration while preserving the no slip condition is (independent of the mass of the car):

<math>\mu_sg</math>

Here <math>g</math> denotes the value of [[acceleration due to gravity]].

===On an incline===

We need to use the model of [[rolling motion along an inclined plane]]. {{fillin}}