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Testing
e 2 π 3 2 t 3 + 1 + 4 {\displaystyle {\frac {e^{2\pi {\sqrt {3}}}}{2t^{3}+1+4}}}
7 + 2 ! ! + 0 = 720 {\displaystyle {\sqrt {7+2}}!!+0=720}
5 1 + 2 = 125 {\displaystyle 5^{1+2}=125}
